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2a^2-4a-7a+2a^2+6a-14=0
We add all the numbers together, and all the variables
4a^2-5a-14=0
a = 4; b = -5; c = -14;
Δ = b2-4ac
Δ = -52-4·4·(-14)
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{249}}{2*4}=\frac{5-\sqrt{249}}{8} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{249}}{2*4}=\frac{5+\sqrt{249}}{8} $
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